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3. At time \(t = 0\), a projectile \((m_p = 7.26\text{ kg})\) is launched over level ground, with this initial velocity: \(v_{Pi} = 83.5\text{ m/s }\angle 71.6^\circ\) (where \(\angle 0^\circ\) is east and \(\angle 90^\circ\) is vertically upward) At time \(t = 2.54\text{ s}\), the projectile explodes into two pieces, A and B, whose velocities immediately after the explosion are partially known: \(v_{Ai} = v_A \angle 90.0^\circ\) (speed unknown) \(v_{Bi} = 52.625\text{ m/s }\angle 41.3^\circ\) Also known: Piece B is twice as massive as piece A. Assuming \(g = 9.80\text{ m/s}^2\), you need to calculate \(J_{EA}\), the impulse exerted by the earth on piece A, while piece A is a projectile (and express your answer as a magnitude and a \(\angle\) direction). But do this calculation two different ways: a. Use the actual definition of impulse, \(J_{EA}\) b. Calculate \(\Delta P_A\), the change in piece A's linear momentum, while it is a projectile.

          3. At time \(t = 0\), a projectile \((m_p = 7.26\text{ kg})\) is launched over level ground, with this initial velocity:
\(v_{Pi} = 83.5\text{ m/s }\angle 71.6^\circ\)
(where \(\angle 0^\circ\) is east and \(\angle 90^\circ\) is vertically upward)
At time \(t = 2.54\text{ s}\), the projectile explodes into two pieces, A and B, whose velocities immediately after the explosion
are partially known:
\(v_{Ai} = v_A \angle 90.0^\circ\) (speed unknown)
\(v_{Bi} = 52.625\text{ m/s }\angle 41.3^\circ\)
Also known: Piece B is twice as massive as piece A.
Assuming \(g = 9.80\text{ m/s}^2\), you need to calculate \(J_{EA}\), the impulse exerted by the earth on piece A, while piece A is a
projectile (and express your answer as a magnitude and a \(\angle\) direction). But do this calculation two different ways:
a. Use the actual definition of impulse, \(J_{EA}\)
b. Calculate \(\Delta P_A\), the change in piece A's linear momentum, while it is a projectile.

3. At time t = 0, a projectile (mp = 7.26 kg) is launched over level ground, with this initial velocity:
vPi = 83.5 m/s ∠ 71.6^∘
(where ∠ 0^∘ is east and ∠ 90^∘ is vertically upward)
At time t = 2.54 s, the projectile explodes into two pieces, A and B, whose velocities immediately after the explosion
are partially known:
vAi = vA ∠ 90.0^∘ (speed unknown)
vBi = 52.625 m/s ∠ 41.3^∘
Also known: Piece B is twice as massive as piece A.
Assuming g = 9.80 m/s^2, you need to calculate JEA, the impulse exerted by the earth on piece A, while piece A is a
projectile (and express your answer as a magnitude and a ∠ direction). But do this calculation two different ways:
a. Use the actual definition of impulse, JEA
b. Calculate Δ PA, the change in piece A's linear momentum, while it is a projectile.

Added by Mark C.

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