00:01
To what volume do you need to dilute 20 m l of a 1 .4 molar solution of mercury sinate to make a .0933 molar solution of mercury sinait 2.
00:11
Okay and how much matter we have to added.
00:14
So what we will do? we will do m1 v1 equal to m2 v2 formula.
00:21
Okay, so m1 is given 1 .4 and 1 .4 and v1 is given 20 ml.
00:30
Okay, m2 is given 0 .0 .093 multiply v2.
00:39
So v2 is what? v2 is given 300 ml, 300m.
00:51
It is the v2.
00:52
Now we have to calculate volume of the water that is added.
00:57
So final volume 300 m.
01:00
Initial volume 20ml.
01:02
Then how much volume of water will be added? so volume of the water will be equal to 300 minus 20.
01:11
That will be equal to 280 ml.
01:15
Okay.
01:17
In the second part, a 100m.
01:19
Solver containing 0 .5 mercury nitrate, read with the 50ml solution containing one mother of sodium sulfate.
01:28
So first we have to add the balance chemical equation.
01:32
Mercury nitrate hg -no3 plus mercury.
01:40
Nitrate plus sodium sulfate, n .a2so4 that will give what that we are getting hg2so4 plus 2 mole of the nano3...