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Hi.
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Here in this given problem there is a circuit having two loops closed loops.
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The first one is having a resistance of 2 oom, another 1 8 oom and a battery providing a voltage of 5 volt.
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Then another loop this is having a resistance of 4 oom.
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Then a cell.
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Of 3 volt and this one is also closed here.
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The current coming out of this cell that is i1.
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Suppose this is junction a here the current going through this 8 -oom that is i2 and this current here in the 4 -oom that is i 3 potential drop across 2 -oom that is v1 across at home this is v2 and across 4 -oom forum this is v3.
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Now first of all in order to find i1 v1 i 2 v2 i 3 v3 all using kirchhoff's junction rule at the junction a this i 1 will be divided into two parts i 2 and i 3 or we can say i 3 is equal to i 1 minus i 2.
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So first of all in these two loops loop 1 and loop 2 using kirchhoff's loop rule.
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It says the algebraic sum of potential drops.
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Algebraic sum means the potential drop which is taking place in clockwise direction that will be that will be taken as positive while that taking place in counterclockwise direction which will be taken as negative.
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And emf which is sending the current in clockwise direction that will be taken as positive and the emf which is sending the current in anti -clockwise direction, counter -clockwise direction that will be taken as negative...