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Balance the half reactions below in alkaline solution. Write the net ionic equation and determine $E^\circ_{cell}$ and $\Delta G^\circ_{cell}$. $Ag_2O(s) \rightarrow Ag(s)$ $E^\circ_{cell} = 0.342V$ $Zn(OH)_2(s) \rightarrow Zn(s) + 2OH^-(aq)$ $E^\circ_{cell} = -1.249V$ 

          Balance the half reactions below in alkaline solution. Write the net ionic equation and determine $E^\circ_{cell}$ and $\Delta G^\circ_{cell}$.
$Ag_2O(s) \rightarrow Ag(s)$  $E^\circ_{cell} = 0.342V$
$Zn(OH)_2(s) \rightarrow Zn(s) + 2OH^-(aq)$ $E^\circ_{cell} = -1.249V$
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Balance the half reactions below in alkaline solution. Write the net ionic equation and determine E^∘cell and Δ G^∘cell. Ag2O(s) → Ag(s) E^∘cell = 0.342V Zn(OH)2(s) → Zn(s) + 2OH^-(aq) E^∘cell = -1.249V

Added by William W.

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Chemistry: Structure and Properties
Chemistry: Structure and Properties
Nivaldo Tro 2nd Edition
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Balance the half reactions below in alkaline solution. Write the net ionic equation and determine E cell and G"cell. AgO(s) - Ag(s) E cell = 0.342V Zn(OH)2(s) - Zn(s) + 2OH-(aq) E cell = -1.249V
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Transcript

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00:04 Let's balance the following in acidic solutions.
00:07 For a, we have zinc solid, 2 plus, v3 +, break this apart into two separate half reactions.
00:33 Two electrons on the right to balance.
00:42 Balance the oxygens by adding h2o.
00:49 Balance the hydrogens by adding 2h plus.
00:53 And let's go ahead and balance the charge.
00:56 Here by adding one electron in order to cancel out the electrons multiply the zinc half reaction by one multiply the vanadium half reaction by two let's rewrite these here electrons cancel balanced equation so here is our balanced equation in acidic solution for b unbalanced we have ag solid, no3 minus, ag plus, then no2 gas.
02:23 First half reaction, second half reaction.
02:36 Let's balance the oxygen by adding h2o to the right.
02:43 Let's balance the hydrogen by adding 2h plus to the left.
02:47 And now let's go ahead and balance the charge by adding one electron to the left.
02:56 One electron on your side that cancels right away, and we are left with ag plus, add n03 minus, add 2h plus, will produce ag plus, add no2 gas, add h2o liquid, and there is our balanced reaction in acidic solution.
03:24 For c, unbalanced, we have magnesium solid, add v043 plus, will produce magnesium 2 plus, and v2 plus, breaking this apart into two half reactions...
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