Question

A force of 400 N is applied onto a beam supported by a pin and cable. (a) Draw a free-body diagram of the beam. (b) Write the equations of equilibrium, $\sum F_x = 0$, $\sum F_y = 0$, and $\sum M = \sum Fd$. (c) Determine the support reactions at pin A and cable B.

          A force of 400 N is applied onto a beam supported by a pin and cable.
(a) Draw a free-body diagram of the beam.
(b) Write the equations of equilibrium, $\sum F_x = 0$, $\sum F_y = 0$, and $\sum M = \sum Fd$.
(c) Determine the support reactions at pin A and cable B.

A force of 400 N is applied onto a beam supported by a pin and cable.
(a) Draw a free-body diagram of the beam.
(b) Write the equations of equilibrium, ∑ Fx = 0, ∑ Fy = 0, and ∑ M = ∑ Fd.
(c) Determine the support reactions at pin A and cable B.

Added by James T.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Satish Kumar

Step 1

At pin A, there will be a vertical reaction force (RAy) and a horizontal reaction force (RAx). Since the beam is in equilibrium, the sum of the vertical forces must be zero. Therefore, RAy = 400 N. At cable B, there will be a tension force (TB) acting upwards. Show more…

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5m: Determine the support reactions at pin A and cable B. b) Write the equations of equilibrium: Î£F = 0, 2F0, and Î£M = Î£Fd. c) Draw a free-body diagram of the beam. 400N: A force of 400 N is applied onto a beam supported by pin A and cable B. 2m: 0 = Î£Pa3 = Î£W3 = 2F = 0 = 33.