00:02
Hello students, according to the given question we have to find mean, median and more values.
00:10
So they have given the data regarding classes and frequencies.
00:15
So class frequency, mid values that is denoted as x and d values is equal to x minus a by h and f into d values and cumulative values.
00:31
Frequency values.
00:34
So given that classes 40 to 44, 45 to 59, 60 to 64, 65 to 64, 65 to 69 and 70 to 74.
00:51
Now the frequencies are 19, 32, 49, 29, and 21.
01:00
So total is 150.
01:03
Here the mid values are here 42, 52, 62, 62, 672.
01:12
Here it is the a value.
01:15
So here the d values are minus 20, minus 10, 0, 5 and 10.
01:22
So by multiplying frequencies and d we get minus 380, minus 320, 0, 145 and 210.
01:35
So the total is minus 345.
01:40
Here the cumulative frequencies are 1951, 100, 129, 150.
01:50
So this is the required table.
01:53
So in the first bit we have to find the mean that is equal to a plus summation fd is divided by n into h.
02:03
So by substituting 62 plus minus 345 is divided by n is the total frequency that is 150 into 1, which is equal to 62 minus 2 .3 which is equal to 59 .7.
02:24
So that mean is equal to 59 .7.
02:30
Now in the second one we have to calculate more that is equal to.
02:35
2, l plus f1 minus f0 is divided by 2f1 minus f2 minus f0 into h.
02:46
So from the above table, f1 means highest frequency that is 49.
02:53
So f0 is the above of f1 that is 32 and f2 is the below of f1 that is 29 and l is the corresponding according frequency 49 class is 60...