Question

Consider the following transfer function: $G(s) = \frac{Y(s)}{U(s)} = \frac{3e^{-s}}{10s + 1}$ a) What is the steady-state gain? b) What is the time constant? c) If U(s) = 4/s, what is the value of the output y(t) when t ? ??

          Consider the following transfer function:
$G(s) = \frac{Y(s)}{U(s)} = \frac{3e^{-s}}{10s + 1}$
a) What is the steady-state gain?
b) What is the time constant?
c) If U(s) = 4/s, what is the value of the output y(t) when t ? ??

Consider the following transfer function:
G(s) = (Y(s))/(U(s)) = (3e^-s)/(10s + 1)
a) What is the steady-state gain?
b) What is the time constant?
c) If U(s) = 4/s, what is the value of the output y(t) when t ? ??

Added by Robin J.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Lottie Adams

Step 1

Step 1: Write the given transfer function: G(s) = 3 e^{-s} / (10 s + 1). Show more…

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Please show your work, I always give positive feedback for correct work. Consider the following transfer function: Y(s) = 3e^(-s) G(s) = U(s) / (10s + 1) a) What is the steady-state gain? b) What is the time constant? c) If U(s) = 4/s, what is the value of the output y(t) when t -> âˆž?