5. $f(t) = t^2$; $[0,4]$ 5 Find all values of \"t\" for $f(t)$ in the stated interval that satisfy the Mean-Value Theorem for Integrals.
Added by Marcus J.
Close
Step 1
To find the average value of f(t) over the interval [0,4], we need to calculate the definite integral of f(t) over that interval and divide it by the length of the interval. The definite integral of f(t) = t^2 over the interval [0,4] is given by: ∫[0,4] t^2 dt = Show more…
Show all steps
Your feedback will help us improve your experience
Rahul Kumar and 81 other Geometry educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Find the average value of f(t) = -2te^(-t^2) on the interval [0,4].
Avinash V.
Find the average value of the function over the given interval. f(t) = e^(0.02t) on [0, 10]
Andrew N.
Evaluate the following definite integrals. $$\int_{0}^{\pi / 4}\left(\sec ^{2} t \mathbf{i}-2 \cos t \mathbf{j}-\mathbf{k}\right) d t$$
Vectors and Vector-Valued Functions
Calculus of Vector-Valued Functions
Recommended Textbooks
Geometry A Common Core Curriculum
Geometry
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD