1. A random sample of 25 patients had a pain score average with a mean of 2.86. Past studies have shown that the standard deviation is 0.15 and the population is normally distributed. • Construct a 90%, 95% and 99% confidence interval for the population mean pain score average. • Interpret all results. 2. A 98% CI for the mean computed from the information in a random sample of n = 122 observation is 97.6 to 104.2 • Interpret this CI • Does this CI support the claim that mean = 100? Explain • Would a 95% CI have been wider or narrower than this 98% CI? Explain
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4. A simple random sample of size 35 has a sample mean of 34.85 and a sample standard deviation of 17.9. a) Construct a 98% confidence interval for the population mean. Show all steps in your method. b) If the confidence level was 95%, would the confidence interval be narrower or wider. Explain why.
Adi S.
Suppose we wanted to test the idea that a control group of cancer patients (Group 1) would report higher mean pain ratings than an experimental group receiving special massage treatments (Group 2). Use the following information to compute a t-statistic for independent groups: mean group 1 = 78.1 SD1 (variance) = 49.1 n1 = 25 mean group 2 = 74.1 SD2 (variance) = 59.7 n2 = 25 What are the degrees of freedom and the value of t? Using α=0.05 for a two-tailed test, is this t statistic significant? Show your calculations for full credit.
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A sample of size n = 15 has a sample mean x and a sample standard deviation s. (a) Construct a 95% confidence interval for the population mean 9bc. (b) If the sample size were n = 25 and the sample standard deviation was unchanged, would the 95% confidence interval be narrower or wider? Why? (c) Construct a 98% confidence interval for the population mean 9bc.
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