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1. A random sample of 25 patients had a pain score average with a mean of 2.86. Past studies have shown that the standard deviation is 0.15 and the population is normally distributed. • Construct a 90%, 95% and 99% confidence interval for the population mean pain score average. • Interpret all results. 2. A 98% CI for the mean computed from the information in a random sample of n = 122 observation is 97.6 to 104.2 • Interpret this CI • Does this CI support the claim that mean = 100? Explain • Would a 95% CI have been wider or narrower than this 98% CI? Explain

          1. A random sample of 25 patients had a pain score average with a mean of 2.86. Past studies have shown that the standard deviation is 0.15 and the population is normally distributed.
• Construct a 90%, 95% and 99% confidence interval for the population mean pain score average.
• Interpret all results.
2. A 98% CI for the mean computed from the information in a random sample of n = 122 observation is 97.6 to 104.2
• Interpret this CI
• Does this CI support the claim that mean = 100? Explain
• Would a 95% CI have been wider or narrower than this 98% CI? Explain
        
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1. A random sample of 25 patients had a pain score average with a mean of 2.86. Past studies have shown that the standard deviation is 0.15 and the population is normally distributed.
• Construct a 90%, 95% and 99% confidence interval for the population mean pain score average.
• Interpret all results.
2. A 98% CI for the mean computed from the information in a random sample of n = 122 observation is 97.6 to 104.2
• Interpret this CI
• Does this CI support the claim that mean = 100? Explain
• Would a 95% CI have been wider or narrower than this 98% CI? Explain

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Elementary Statistics a Step by Step Approach
Elementary Statistics a Step by Step Approach
Allan G. Bluman 9th Edition
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please solve step by step 1.A random sample of 25 patients had a pain score average with a mean of2.86.Past studies have shown that the standard deviation is O.15 and thepopulation is normally distributed. Construct a 90%,95% and 99% confidence interval for the population mean pain score average. Interpret all results 2.A 98% Cl for the mean computed from the information in a randomsample of n =122 observation is 97.6 tc 104.2 eInterpret this CI Does this Cl support the claim that mean100?Explain Would a 95% CI have been wider or narrower than this 98% CI?Explain
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Transcript

-
00:09 We have given in the question that the sample size n is equal to 35, sample mean x bar is equal to 34 .85, standard deviation sigma is equal to 17 .9.
00:26 Now we have to find the 98 % of confidence interval for the population mean.
00:32 For this the degree of freedom is equal to n -1 that is 35 -1 which is equal to 34 and significance level alpha is equal to 0 .02 that is 1 -98 % or it can be also written as 1 -0 .98 which is equal to 0 .02.
01:08 Now based on this information the critical value, critical t value is tc is equal to 2 .441 with the help of the table...
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