Question

Please use the values in the resources listed below instead of the textbook values. Balance the following in basic solution. (Omit states-of-matter from your answer. Use the lowest possible whole number coefficients.) (a) $ClO_3^-(aq) + Cu(OH)_2(s) \rightarrow ClO_4^-(aq) + CuOH(s)$ Oxidation reaction $Cu^{2+} + e^- \rightarrow Cu^+$ Reduction reaction $ClO_3^- \rightarrow ClO_4^- + 2e^-$ Net reaction $ClO_3^- + 2Cu(OH)_2 \rightarrow ClO_4^- + 2CuOH$

Name: please use the values in the resources listed below instead of the textbook values balance the following in basic solution omit states of matter from your answer use the lowest possible whol 73824
Uploaded: 2023-06-07T19:37:30-08:00
Duration: 2 min 37 s
Channel: Nicholas Mogoi
Description: please use the values in the resources listed below instead of the textbook values balance the following in basic solution omit states of matter from your answer use the lowest possible whol 73824

          Please use the values in the resources listed below instead of the textbook values.
Balance the following in basic solution. (Omit states-of-matter from your answer. Use the lowest possible whole number coefficients.)
(a) $ClO_3^-(aq) + Cu(OH)_2(s) \rightarrow ClO_4^-(aq) + CuOH(s)$
Oxidation reaction
$Cu^{2+} + e^- \rightarrow Cu^+$
Reduction reaction
$ClO_3^- \rightarrow ClO_4^- + 2e^-$
Net reaction
$ClO_3^- + 2Cu(OH)_2 \rightarrow ClO_4^- + 2CuOH$

Added by Ashley N.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Nicholas Mogoi

06/07/2023

Step 1

Step 1: The oxidation half-reaction is: $Cu^{2+} + e^- \rightarrow Cu^+$ The reduction half-reaction is: $ClO_3^- \rightarrow ClO_4^- + 2e^-$ Show more…

Show all steps

Thanks for your feedback!

Please use the values in the resources listed below instead of the textbook values. Balance the following in basic solution. (Omit states-of-matter from your answer. Use the lowest possible whole number coefficients.) (a) $ClO_3^-(aq) + Cu(OH)_2(s) \rightarrow ClO_4^-(aq) + CuOH(s)$ Oxidation reaction $Cu^{2+} + e^- \rightarrow Cu^+$ Reduction reaction $ClO_3^- \rightarrow ClO_4^- + 2e^-$ Net reaction $ClO_3^- + 2Cu(OH)_2 \rightarrow ClO_4^- + 2CuOH$