Question

Data Table: Constant Total Mass M1 M2 Run (kg) (kg) aexp (m/s²) Fnet M1+ M2 atheory Percent (N) (kg) (m/s²) difference Run #1 0.090 0.100 Run #2 0.080 0.110 Run #3 0.070 0.120 Data Table: Constant Net Force M1 M2 Run (kg) (kg) aexp (m/s2) Fnet M1+M2 atheory Percent (N) (kg) (m/s²) difference Run #4 0.090 0.100 Run #5 0.040 0.050 Run #6 0.020 0.030

          Data Table: Constant Total Mass
M1
M2
Run
(kg)
(kg)
aexp
(m/s²)
Fnet
M1+ M2 atheory Percent
(N)
(kg)
(m/s²)
difference
Run #1
0.090
0.100
Run #2
0.080
0.110
Run #3
0.070
0.120
Data Table: Constant Net Force
M1
M2
Run
(kg)
(kg)
aexp
(m/s2)
Fnet
M1+M2 atheory Percent
(N)
(kg)
(m/s²)
difference
Run #4
0.090
0.100
Run #5
0.040
0.050
Run #6
0.020
0.030

Data Table: Constant Total Mass
M1
M2
Run
(kg)
(kg)
aexp
(m/s²)
Fnet
M1+ M2 atheory Percent
(N)
(kg)
(m/s²)
difference
Run #1
0.090
0.100
Run #2
0.080
0.110
Run #3
0.070
0.120
Data Table: Constant Net Force
M1
M2
Run
(kg)
(kg)
aexp
(m/s2)
Fnet
M1+M2 atheory Percent
(N)
(kg)
(m/s²)
difference
Run #4
0.090
0.100
Run #5
0.040
0.050
Run #6
0.020
0.030

Added by Laura W.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Linda Winkler

Step 1

We can do this by simply adding the values of M1 and M2. Show more…

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Please use these values to perform the Atwood machine experiment calculations and submit your Excel file that was used to generate the graphs. Don't forget to include tables and graphs. Data Table: Constant Total Mass M1 (kg) M2 (kg) aexp (m/s^2) Fnet (N) M1+M2 (kg) atheory (m/s^2) Percent difference Run Run#1 0.090 0.100 Run#2 0.080 0.110 Run#3 0.070 0.120 Data Table: Constant Net Force M1 (kg) M2 (kg) aexp (m/s^2) Fnet (N) M1+M2 (kg) atheory (m/s^2) Percent difference Run Run#4 0.090 0.100 Run#5 0.040 0.050 Run#6 0.020 0.030