Question

Given the DT system: y[n] - 0.6y[n-1] + 0.08y[n-2] = 4x[n] 28. (4') Find its transfer function H(z). $\frac{4}{z^2 - 0.6z + 0.08}$ a. $H(z) = $ $\frac{4z^2}{z^2 + 0.08z - 0.6}$ b. $H(z) = $ $\frac{4z^2}{z^2 - 0.6z + 0.08}$ c. $H(z) = $ d. other 29. (4') What is its impulse response h[n]? a. $h[n] = (8(0.4)^n - 4(0.2)^n)u[n]$ b. $8(0.4)^n - 4(0.2)^n$ c. $h[n] = 8(-0.4)^n - 4(0.2)^n$ d. other 30. (2') Is the above system stable? a. Yes, it is stable. b. No, it is unstable.

          Given the DT system: y[n] - 0.6y[n-1] + 0.08y[n-2] = 4x[n]
28.
(4') Find its transfer function H(z).
$\frac{4}{z^2 - 0.6z + 0.08}$
a. $H(z) = $
$\frac{4z^2}{z^2 + 0.08z - 0.6}$
b. $H(z) = $
$\frac{4z^2}{z^2 - 0.6z + 0.08}$
c. $H(z) = $
d. other
29.
(4') What is its impulse response h[n]? 
a. $h[n] = (8(0.4)^n - 4(0.2)^n)u[n]$
b. $8(0.4)^n - 4(0.2)^n$
c. $h[n] = 8(-0.4)^n - 4(0.2)^n$
d. other
30.
(2') Is the above system stable?
a. Yes, it is stable. b. No, it is unstable.

Given the DT system: y[n] - 0.6y[n-1] + 0.08y[n-2] = 4x[n]
28.
(4') Find its transfer function H(z).
(4)/(z^2 - 0.6z + 0.08)
a. H(z) =
(4z^2)/(z^2 + 0.08z - 0.6)
b. H(z) =
(4z^2)/(z^2 - 0.6z + 0.08)
c. H(z) =
d. other
29.
(4') What is its impulse response h[n]?
a. h[n] = (8(0.4)^n - 4(0.2)^n)u[n]
b. 8(0.4)^n - 4(0.2)^n
c. h[n] = 8(-0.4)^n - 4(0.2)^n
d. other
30.
(2') Is the above system stable?
a. Yes, it is stable. b. No, it is unstable.

Added by Catherine L.

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