Point charges q1 = 50 μC and q2 = -25 μC are placed 1.0 m apart. What is the force on a third charge q3 = 20 μC placed midway between q1 and q2?
Added by Pilar J.
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99 \times 10^9 \frac{50 \times 20 \times 10^{-6} \times 10^{-6}}{(0.5)^2} \] \[ F_{13} = 8.99 \times 10^9 \times 0.0001 \times 10^{-6} \times 40 \] \[ F_{13} = 8.99 \times 10^3 \times 4 \] \[ F_{13} = 35.96 \times 10^3 \text{ N} \] Show more…
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