00:01
In this problem, we are given that there's a binomial random variable x, and we have to find out the mean, variance, and the standard deviation in each case, represented by mu, v, and sigma, respectively.
00:13
So in the first case, the number of trials is 4, probability of the success is 0 .4.
00:18
So let's first find out the probability of the failure by subtracting p from 1.
00:23
So we will get 0 .6 as the result.
00:25
And let's use this formula to get the mean, according to which the mean value will be n times p, which comes out to be 1 .6.
00:34
And now we can use this formula and get the variance.
00:36
So this will be n times p into q, and multiplying them, we will get 0 .96 as the result.
00:44
And the standard deviation, well, that will be the square root of the variance, which comes out to be 0 .98 approximately.
00:52
And in the next part, the number of trials, this is 5, probability of the success, that's 0 .6.
00:58
So the probability of the failure, this will be 1 minus p, which comes out to be 0 .4.
01:04
So the mean value, it will be n times p again, which will be 3.
01:08
The variance, that will be n times p into q, which comes out to be 1 .2...