00:01
Hello, so we have a purson distribution with a mean of 3 .6 per week.
00:08
So lambda is 3 .6 per week.
00:19
Before, let's look at the formula for purson distribution.
00:25
It's e to the negative lambda times lambda to the x over x factorial.
00:35
Okay, now a, we want to find the probability there are no accidents, okay, in one.
00:41
Week so we are finding probability of x equals 0 is going to be e to the negative 0 .6 times 30 .6 is putting 0 over 0 factorial so this is just e to the negative 3 .6 e to the negative 3 .6 e to the negative 3 .6 to 4 decimal places we're going to have 0 .073 the next one is the probability that six or more accidents as probability of x greater than or equal to 6.
01:41
This is the same as 1 minus the probability of x less than or equal to 5.
01:50
So let's look at what this means.
01:55
What this means is that we have to do probability from x to 0 all the way up to probability that x equals 5.
02:12
So we can see that this is going to be a lot of work.
02:14
So the alternative is to use excel.
02:18
So let's look at using excel.
02:24
So we are using excel for the one in bracket.
02:27
So for excel, we're just going to type in equal to puisson.
02:37
Our first entry is going to be 5.
02:41
The next one is our mean value, 3 .6.
02:44
And we're going to type here true.
02:49
So we type in true because we want the probability from 0 to 5.
02:56
Okay, so we have to put in true...