00:01
Okay, so we've got a question about rolling a fair dice 102 times, and we want to record x, which is the number of sixes in 102 rolls.
00:11
The first question is just about the distribution of x.
00:15
So we've got 102 trials, and the probability of getting a six at each occasion is a sixth.
00:21
So we can see that x just follows a binomial distribution with n equals 120, no 120, n equals 102 rolls or trials.
00:30
And the probability of success, i .e.
00:33
The probability of getting a six is one -sixth.
00:37
The mean, therefore, a binomial distribution, the mean is np, or 102 times 1 over 6, which is 17.
00:46
And the standard deviation is given by the square root of the variance, which is np times 1 minus p.
00:52
So that's 102 times a 6th times 5 -6th, and then square rooted, which is 3 .76.
01:00
7 .6.
01:03
Part b then asks about the proportion of tosses that show a six.
01:09
And we want to know what we can say about the distribution of the proportion.
01:13
Well, the proportion is the sample proportion is going to follow a normal distribution with mean given by the population proportion, which we know is a sixth.
01:27
A sixth of the rolls should be a six...