00:01
Here we are given a normal window is a rectangle with a semicircle on top given diagram is like this.
00:14
Now it requires 24 feet to trim on the outer edges.
00:21
We need to find what dimensions will allow to maximum amount of light to enter a house.
00:27
Here we see that this is height given with y and this is the radius that is x.
00:37
Of the semicircle.
00:40
Now you will find the perimeter of the given window.
00:47
To find the perimeter that is contain perimeter of rectangle plus perimeter of semicircle.
01:02
Perimeter of rectangle, perimeter of rectangle, that is x plus x because this is 2x plus y, plus x, because this is 2x, plus y, plus y we don't consider this side this side we don't consider it now parameter of semicircle that is here radius is x that is pi times r here are radius that is x now simplify it now simplify it be equal to 2x plus pi x plus pi x plus 2 y we know that value of 5 that is 3 .14 2x plus 3 .14 x plus 2y.
02:07
Here given that total outrage is 24, so perimeter 8, 24, that is equal to 2 plus 3 .14, that is 5 .14x plus 2y.
02:26
Now solve for y, we get 12 minus 2 .57x.
02:41
Now we will find the area of the window, that is, area of the window, that is, area of the rectangle plus area of the semicircle...