Question

Beth wants to determine a 90 percent confidence interval for the true proportion of high school students in the area who attend their home basketball games. How large of a sample must she have to get a margin of error less than 0.03? Assume we have no prior estimate of the proportion and want a conservative choice for the sample size. [Round to the smallest integer that works.] n =

          Beth wants to determine a 90 percent confidence interval for the true proportion of high school students in the area who attend their home basketball games. How large of a sample must she have to get a margin of error less than 0.03? Assume we have no prior estimate of the proportion and want a conservative choice for the sample size.

[Round to the smallest integer that works.] n =

Beth wants to determine a 90 percent confidence interval for the true proportion of high school students in the area who attend their home basketball games. How large of a sample must she have to get a margin of error less than 0.03? Assume we have no prior estimate of the proportion and want a conservative choice for the sample size.

[Round to the smallest integer that works.] n =

Added by Jessica C.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

Instant Answer

Solved by Expert Sri K

06/28/2022

Step 1

Given that the confidence level is 90%, the significance level alpha is 0.1. To find the critical value, divide alpha by 2: alpha/2 = 0.1/2 = 0.05. Look up the z-score for a 95% confidence level (since 90% is not directly available) which is approximately 1.645. Show more…

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Beth wants to determine a 90 percent confidence interval for the true proportion of high school students in the area who attend their home basketball games. How large of a sample must she have to get a margin of error less than 0.03? Assume we have no prior estimate of the proportion and want a conservative choice for the sample size. (Round to the smallest integer that works)