Question

POSSIBLE POINTS: 6 A 0.5-kg mass is tied to a 3-meter string and spun at 1.5 revolutions per second. The string has a tensile strength of 500 Newtons. At what angular velocity does the string break? 2.3 revolutions per second 3.4 revolutions per second 2.9 revolutions per second 1.8 revolutions per second

          POSSIBLE POINTS: 6
A 0.5-kg mass is tied to a 3-meter string and spun at 1.5 revolutions per second. The string has a tensile strength of 500 Newtons. At what angular velocity does the string break?
2.3 revolutions per second
3.4 revolutions per second
2.9 revolutions per second
1.8 revolutions per second

POSSIBLE POINTS: 6
A 0.5-kg mass is tied to a 3-meter string and spun at 1.5 revolutions per second. The string has a tensile strength of 500 Newtons. At what angular velocity does the string break?
2.3 revolutions per second
3.4 revolutions per second
2.9 revolutions per second
1.8 revolutions per second

Added by Michelle V.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Dharmendra Maheshwari

04/24/2022

Step 1

The centripetal force can be calculated using the formula F = m * (v^2 / r), where m is the mass, v is the velocity, and r is the radius of the circular motion. In this case, m = 0.5 kg, v = 2π * 1.5 (since 1.5 revolutions per second is equivalent to 1.5 * 2π Show more…

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POSSIBLE POINTS: 6 A 0.5-kg mass is tied to a 3-meter string and spun at 1.5 revolutions per second. The string has a tensile strength of 500 Newtons. At what angular velocity does the string break? O 2.3 revolutions per second O 3.4 revolutions per second O 2.9 revolutions per second O 1.8 revolutions per second