Possible values of X, the number of components in a system submitted for repair that must be replaced, are 1, 2, 3, and 4 with corresponding probabilities 0.05, 0.05, 0.45, and 0.45, respectively. (a) Calculate E(X) and then E(5 − X).
Added by Larry T.
Step 1
05) + 2(0.05) + 3(0.45) + 4(0.45) = 0.05 + 0.10 + 1.35 + 1.80 = 3.30 Show more…
Show all steps
Close
Your feedback will help us improve your experience
Rosina Dapaah and 52 other Intro Stats / AP Statistics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Possible values of X, the number of components in a system submitted for repair that must be replaced, are 1, 2, 3, and 4 with corresponding probabilities .15, .35, .35, and .15, respectively. a. Calculate E(X) and then E(5 - X). b. Would the repair facility be better off charging a flat fee of $75 or else the amount $[150/(5 - X)]? [Note: It is not generally true that E(c/Y) = c/E(Y).]
Rosina D.
Possible values of X, the number of components in a system submitted for repair that must be replaced, are 1, 2, 3, and 4 with corresponding probabilities 0.05, 0.05, 0.45, and 0.45, respectively. (a) Calculate E(X) and then E(5 - X). E(X) = E(5 - X) = (b) Would the repair facility be better off charging a flat fee of $110 or else the amount $[150/(5 - X)]$? Note: It is not generally true that E(c/Y) = c/E(Y) The repair facility ---Select--- be better off charging a flat fee of $110 because E[150/(5 - X)] =
Adi S.
William F.
Recommended Textbooks
Elementary Statistics a Step by Step Approach
The Practice of Statistics for AP
Introductory Statistics
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD