Question

VCC 18V R1 Rc C B 2N2222A E R2 Re Fig. 6. BJT biasing circuit

          VCC 18V
R1 Rc
C
B
2N2222A
E
R2 Re
Fig. 6. BJT biasing circuit

Added by Cristian J.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Nishant Kumar

Step 1

Determine the value of RC: To operate the transistor in the active region with IC = 5mA, we can use the formula: RC = (VCC - VCE) / IC Given that VCC = 18V and VCE = 1/2 VCC = 9V, we can calculate RC: RC = (18V - 9V) / 5mA = 9V / 5mA = 1.8kΩ Show more…

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Post Lab Task: Design of a BJT Biasing Circuit (Amplifier) With the help of the attached transistor datasheet (2N2222), determine the values of RC, RE, R1, and R2 so that the transistor in Fig. 6 operates in the active region with IC = 5mA (Use Approximate Analysis method). Simulate your circuit and measure VCE, IC, and VC. Compare the values in (2) with your design values. Comment on the results. Assumptions: Vce = ½ Vcc, Hfe = 60 as per the datasheet. For stability, select Ve = 1/10 of Vcc or a little higher. Implement this circuit in your Multisim and take screenshots with the voltages and current values.