Question

Potassium superoxide, KO2, reacts with carbon dioxide to form potassium carbonate and oxygen: 4KO2 + 2CO2 ? 2K2CO3 + 3O2 This reaction makes potassium superoxide useful in a self-contained breathing apparatus. How much O2 could be produced from 2.51 g of KO2 and 4.44 g of CO2?

          Potassium superoxide, KO2, reacts with carbon dioxide to form potassium carbonate and oxygen:
4KO2 + 2CO2 ? 2K2CO3 + 3O2
This reaction makes potassium superoxide useful in a self-contained breathing apparatus. How much O2 could be produced from 2.51 g of KO2 and 4.44 g of CO2?

Potassium superoxide, KO2, reacts with carbon dioxide to form potassium carbonate and oxygen:
4KO2 + 2CO2 ? 2K2CO3 + 3O2
This reaction makes potassium superoxide useful in a self-contained breathing apparatus. How much O2 could be produced from 2.51 g of KO2 and 4.44 g of CO2?

Added by Daniel E.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Adi S

09/14/2023

Step 1

The molar mass of KO₂ is 39.10 (K) + 32.00 (O₂) = 71.10 g/mol. The molar mass of CO₂ is 12.01 (C) + 32.00 (O₂) = 44.01 g/mol. Now, we can find the number of moles of each reactant: moles of KO₂ = 2.51 g / 71.10 g/mol = 0.0353 mol moles of CO₂ = 4.44 g / 44.01 Show more…

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Potassium superoxide, KO2, reacts with carbon dioxide to form potassium carbonate and oxygen: 4KO2 + 2CO2 ⟶ 2K2CO3 + 3O2 This reaction makes potassium superoxide useful in a self-contained breathing apparatus. How much O2 could be produced from 2.51 g of KO2 and 4.44 g of CO2?