00:01
So here in this question we are considering a controlled half wave rectifier with the resistance load is what we are considering here.
00:06
So here we are given a half wave rectifier.
00:10
So for this we can say that v0 from here is equals to v of m that is divided by 2 pi which is multiplied by 1 plus cos of alpha.
00:18
So this is given to us this is for the r load is what we are considering here.
00:24
So the value of v of m from here is equals to 120 multiplied by under root 2 volt and the value of v0 from here is equals to 40 volt where the value of resistance r is equals to 100 ohm.
00:34
So we can plug the value in the formula which we just discussed here.
00:38
So this from here is equals to 40 is equals to 120 multiplied by under root 2 that is divided by 2 pi multiplied by 1 plus cos of alpha.
00:46
So this is what we are given here.
00:48
Now simplify the term we get the value of alpha that become equals to 61 .25 degree.
00:52
So this is the value of the alpha from here.
00:54
Now the value of v0 of rm is from here is equals to under root 1 that is divided by 2 pi integral that is from alpha to pi of v of m multiplied by the sin of omega t to its whole square which is multiplied by d of omega t from here.
01:09
So that from here is equals to under root v of m divided by the 2 pi to its whole square multiplied by omega of t that is divided by 2 minus sin of 2 of omega t that is divided by 4...