For the structure shown below, find the tension forces in cables CA, CB, CD, and DE.
F.B.D. of Point C
FCA
FCB
FCD
F.B.D. of Point D
FCD
FDE
W = 150 kg (9.81 m/s^2)
150 kg
Answers
FCB = 1490 N
FCA = 2220 N
FCD = 2450 N
FCD = 2450 N
FDE = 1960 N
W = 150 kg (9.81 m/s^2) = 1470 N