Question

Practice Final Exam haileygray Project2 - Goog ses/553449/quizzes/1547338/take Question 1 Solve the linear initial value problem. \[ x \frac{d y}{d x}-y=x^{3} e^{x}, y(1)=e \] ? \( y(x)=x^{2} e^{x}-2 x e^{x}+2 e^{x} \) ? \( y(x)=x^{3} e^{x}-2 x^{2} e^{x}+2 x e^{x} \) ? \( y(x)=x-2 e^{x}+\frac{2}{x} e^{x}+e-1 \) ? \( y(x)=x^{2} e^{x}-x e^{x}+e x \) ? \( y(x)=\frac{1}{4} x^{4} e^{x}+\frac{3}{4} e^{x} \) Question 2 Find the implicit general solution to the given separable differential equation. \[ \left(x^{3}+7 x^{3} y^{4}\right) d x+e^{x^{4}} y^{3} d y=0 \] ? \[ \ln \left(1+7 y^{4}\right)-\frac{1}{}=C \] Search

          Practice Final Exam
haileygray Project2 - Goog
ses/553449/quizzes/1547338/take

Question 1

Solve the linear initial value problem.
\[
x \frac{d y}{d x}-y=x^{3} e^{x}, y(1)=e
\]
? \( y(x)=x^{2} e^{x}-2 x e^{x}+2 e^{x} \)
? \( y(x)=x^{3} e^{x}-2 x^{2} e^{x}+2 x e^{x} \)
? \( y(x)=x-2 e^{x}+\frac{2}{x} e^{x}+e-1 \)
? \( y(x)=x^{2} e^{x}-x e^{x}+e x \)
? \( y(x)=\frac{1}{4} x^{4} e^{x}+\frac{3}{4} e^{x} \)

Question 2

Find the implicit general solution to the given separable differential equation.
\[
\left(x^{3}+7 x^{3} y^{4}\right) d x+e^{x^{4}} y^{3} d y=0
\]
?
\[
\ln \left(1+7 y^{4}\right)-\frac{1}{}=C
\]

Search
        
Show more…
Practice Final Exam
haileygray Project2 - Goog
ses/553449/quizzes/1547338/take

Question 1

Solve the linear initial value problem.

    x (d y)/(d x)-y=x^3 e^x, y(1)=e

? y(x)=x^2 e^x-2 x e^x+2 e^x
? y(x)=x^3 e^x-2 x^2 e^x+2 x e^x
? y(x)=x-2 e^x+(2)/(x) e^x+e-1
? y(x)=x^2 e^x-x e^x+e x
? y(x)=(1)/(4) x^4 e^x+(3)/(4) e^x

Question 2

Find the implicit general solution to the given separable differential equation.

    (x^3+7 x^3 y^4) d x+e^x^4 y^3 d y=0

?

    ln(1+7 y^4)-(1)/()=C


Search

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Calculus: Graphical, Numerical, Algebraic
Calculus: Graphical, Numerical, Algebraic
Ross L. Finney, Franklin D. Demana, Bet… 5th Edition
Chapter 7
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Practice Final Exam haileygray Project2 - Goog ses/553449/quizzes/1547338/take Question 1 Solve the linear initial value problem. \[ x \frac{d y}{d x}-y=x^{3} e^{x}, y(1)=e \] ◯ \( y(x)=x^{2} e^{x}-2 x e^{x}+2 e^{x} \) ◯ \( y(x)=x^{3} e^{x}-2 x^{2} e^{x}+2 x e^{x} \) ◯ \( y(x)=x-2 e^{x}+\frac{2}{x} e^{x}+e-1 \) ◯ \( y(x)=x^{2} e^{x}-x e^{x}+e x \) ◯ \( y(x)=\frac{1}{4} x^{4} e^{x}+\frac{3}{4} e^{x} \) Question 2 Find the implicit general solution to the given separable differential equation. \[ \left(x^{3}+7 x^{3} y^{4}\right) d x+e^{x^{4}} y^{3} d y=0 \] ◯ \[ \ln \left(1+7 y^{4}\right)-\frac{1}{}=C \] Search
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