00:01
Okay, so the first part, as for the distance of the image, given that the distance of the object is 21 .2 centimeter from the surface, the size of the object, its diameters, 2 .19 centimeter, and the radius of curvature of the spherical surface is 31 .8.
00:33
Note that in this case, the spherical surface resembles a conchase with a radius of curvature is denoted as negative.
00:46
We're given the index of refraction of the glass, which is 1 .5.
00:55
And we know that the index of refraction of air is what.
01:00
So determine the distance of the image from the surface, the spherical refractive.
01:10
We will use this object image relationship of a spherical fracturing surface, which is six.
01:30
Note that a here is the glass in b is the air.
01:40
But you need to isolate distance of the image to the left side.
01:46
So by algebra, the distance of the image is equals to this equation.
01:58
Then inserting the given values, index of fractional air is 1 index of refraction of the glass is 1 .5 the radius of further is negative 31 .8 centimeter and the distance of the object is 21 .2 centimeter and so we can find that the distance of the image is equals negative 18 .2 centimeter...