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Hello everyone.
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Let us see the following question.
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Use vsepr theory to predict the shape of the following molecules and ions.
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So, we have first molecule.
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The first molecule that we are talking about is i.
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F5.
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So, we have to use a vsepr shortcut theory.
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So, in iodine, there are seven valence electron.
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There are five fluorines.
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Each fluorine also has seven valence electron.
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So, so, 7 plus 7 fives are 35.
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So total there are 42 valence electron.
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For our convenience we'll divide it by 8, that means 8 fies are 40.
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So out of 42 electrons will remain, that becomes one lone pair.
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So there is 5 bond pair and 1 lone pair.
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So the central atom iodine has to have total 6 bonds, 1, 2, 3, 4, 5 and 6.
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Out of that one is lp.
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So if there is one lp and 4 bp, what do we call that as this is simply becoming pyramidal shape, isn't it? so it is square pyramidal.
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The next molecule that we are going to speak here is the second one that is xenon tetrafluoride...