Question

Pre-Lab Calculate the mass percent of water (M.W. = 18.02 g/mole) in each of the hydrated salts below to three sig. figs. Compound Molecular Mass CuSO$_4$ \cdot 5 249.68 g/mole H$_2$O BaCl$_2$ \cdot 2 H$_2$O 244.46 g/mole Na$_2$CO$_3$ \cdot 10 286.14 g/mole H$_2$O MgSO$_4$ \cdot 7 246.47 g/mole H$_2$O KAl(SO$_4$)$_2$ 474.37 g/mole \cdot 12 H$_2$O CuSO$_4$ \cdot 5 H$_2$O = % BaCl$_2$ \cdot 2 H$_2$O = % Na$_2$CO$_3$ \cdot 10 H$_2$O = % MgSO$_4$ \cdot 7 H$_2$O = % KAl(SO$_4$)$_2$ \cdot 12 H$_2$O = %

          Pre-Lab
Calculate the mass percent of water (M.W. = 
18.02 g/mole) in each of the hydrated salts
below to three sig. figs.
Compound	Molecular Mass
CuSO$_4$ \cdot 5	249.68 g/mole
H$_2$O
BaCl$_2$ \cdot 2 H$_2$O	244.46 g/mole
Na$_2$CO$_3$ \cdot 10	286.14 g/mole
H$_2$O
MgSO$_4$ \cdot 7	246.47 g/mole
H$_2$O
KAl(SO$_4$)$_2$	474.37 g/mole
\cdot 12 H$_2$O
CuSO$_4$ \cdot 5 H$_2$O = 	%
BaCl$_2$ \cdot 2 H$_2$O = 	%
Na$_2$CO$_3$ \cdot 10 H$_2$O = 	%
MgSO$_4$ \cdot 7 H$_2$O = 	%
KAl(SO$_4$)$_2$ \cdot 12 H$_2$O = 	%

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Pre-Lab
Calculate the mass percent of water (M.W. =
18.02 g/mole) in each of the hydrated salts
below to three sig. figs.
Compound Molecular Mass
CuSO4 ·5 249.68 g/mole
H2O
BaCl2 ·2 H2O 244.46 g/mole
Na2CO3 ·10 286.14 g/mole
H2O
MgSO4 ·7 246.47 g/mole
H2O
KAl(SO4)2 474.37 g/mole
·12 H2O
CuSO4 ·5 H2O = %
BaCl2 ·2 H2O = %
Na2CO3 ·10 H2O = %
MgSO4 ·7 H2O = %
KAl(SO4)2 ·12 H2O = %

Added by Connor P.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Dinesh Singh

Step 1

To do this, we need to multiply the molecular mass of water (18.02 g/mol) by the number of water molecules in each compound. For CuSO4·5H2O: Mass of water = 18.02 g/mol * 5 = 90.1 g/mol For BaCl2·2H2O: Mass of water = 18.02 g/mol * 2 = 36.04 g/mol For Show more…

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Pre-Lab Calculate the mass percent of water (M.W. 18.02 g/mole) in each of the hydrated salts below to three sig.figs Compound Molecular Mass CuSO4Â·5H2O 249.68 g/mole BaCl2Â·2H2O 244.46 g/mole NaCO3Â·10H2O 286.14 g/mole MgSO4Â·7H2O 246.47 g/mole KAl(SO4)2Â·12H2O 474.37 g/mole CuSO4Â·5H2O BaCl2Â·2H2O NaCO3Â·10H2O MgSO4Â·7H2O KAl(SO4)2Â·12H2O

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