00:01
Hello students, so for this question in the first part we have this reaction when nahco3 is reacting with hcl to produce nacl plus water plus co2.
00:14
So, we have to balance this reaction.
00:16
So, let us write so sodium here is 1, hydrogen is 1 plus 1, 2, carbon is 1, oxygen is 3 and chlorine is 1.
00:25
Here in the product side also sodium is 1, hydrogen is 2, carbon is 1, oxygen is 2 plus 1, 3 and chlorine is 1.
00:35
So, since the number of elements, atoms in the reactant side is equal to the number of atoms in the product side, so we can say that this reaction is already a balanced reaction.
00:48
Now in the second question we have to find the reactants to put in beaker.
00:58
So, the reactants that we have for this reaction is number 1 nahco3 that is sodium bicarbonate and hcl that is hydrochloric acid and then in number c we have to write the products that will be formed.
01:23
So, as you can see in the above reaction the products that are formed are nacl, h2o and carbon dioxide.
01:31
So, let us write that.
01:33
So, this is sodium chloride, then we have h2o and then we have carbon dioxide.
01:39
Now out of these three this is earth gas.
01:43
So, that comes us to our fourth question which is which product will fizz away.
01:48
So, we can say that since co2 is a gas, so it will fizz away.
01:59
That means it will form the bubbles in the solution and will go out.
02:05
Now we have two products left.
02:09
So, we can say that the products left are nacl and water and we have to remove one of them to separate them.
02:23
So, since water can be removed easily by the process of evaporation, so we can say that by evaporation water will turn into its gaseous form and leave the product mixture, thus separating the remaining two products.
03:13
Now let's move on to the sixth part.
03:17
So, in the sixth part we have, so our reaction was nahco3 plus hcl giving rise to nacl plus h2o plus co2.
03:28
Now we have one gram of nahco3 and we have to find the amount of nacl produced...