Question

Write a linear equation for the following table. \(x = \text{time}\) \(y = \text{distance}\) \begin{tabular}{|c|c|} \hline 1 & 54 \\ 2 & 73 \\ 3 & 92 \\ 4 & 111 \\ 5 & 130 \\ \hline \end{tabular} y = \underline{\qquad}x + \underline{\qquad}

          Write a linear equation for the following table.
\(x = \text{time}\) \(y = \text{distance}\)
\begin{tabular}{|c|c|}
\hline
1 & 54 \\
2 & 73 \\
3 & 92 \\
4 & 111 \\
5 & 130 \\
\hline
\end{tabular}
y = \underline{\qquad}x + \underline{\qquad}
        
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Write a linear equation for the following table.
x = time y = distance

1     54 

2     73 

3     92 

4     111 

5     130 


y =     x +

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Precalculus with Limits
Precalculus with Limits
Ron Larson 2nd Edition
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Precalculus Program | Dept. Precalculus Program | Dept. date_homework.html Precalculus Program... Return to the Objective MATH 117, Unit 1, Objective 1, Section 1 Section 2 Section 3 Write a linear equation for the following table. able[[x= time, y= distance],[1,54],[2,73],[3,92],[4,111],[5,130]] y = x + Submit this problem for grading. X Precalculus Program Dept. X Precalculus Program Dept. + Get Help date homework.html Precalculus Program... TE UNIVERSITY DEPARTMENT OF MATHEMATICS Return to the Objective MATH 117, Unit 1, Objective 1, Section 1 Section 2 Section 3 Write a linear equation for the following table x - time distance 54 73 92 111 1 2 3 4 5 130 Submit this problem for grading Q Search Y
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Transcript

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00:01 Okay, so i went ahead and drew all the triangles for these problems.
00:04 So we're looking at a 500 centimeter ladder is leaning against the building, forms 57 degrees with the angle or with the ground, how far from the wall is the bottom of the ladder? so that's the value we're looking for.
00:19 Okay.
00:20 So for this trig, we got the adjacent side here, and we got hypotenuse, so we're going to do cosine.
00:26 So cosine of 57 is equal to x over 500.
00:31 So if i multiply both sides by 500 here, 500 times the cosine of 57 is equal to x.
00:39 So 500 times the cosine of 57.
00:50 It's going to give me, says around in the years 10th, 272 .3 centimeters.
01:00 A kite is flying 115 feet above the ground, so that's the 115 here.
01:05 The length of the string is 150 feet, measure from the ground.
01:10 Find the angle to the nearest degree that the string makes to the ground.
01:14 So this is the angle here.
01:15 If we look at what's the references here, this is opposite and this is hypotenuse.
01:20 So that means i could take the sign of my angle theta, and that's equal to 115 over 150.
01:27 So the next step is just taking the inverse sign.
01:35 So the inverse sign of 115 divided by 150 is going to give me to the nearest degree 50 degrees.
01:46 An observation tower is 75 meters tie...
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