00:01
Okay, let's begin by drawing our substrate and reactants.
00:04
So i see a 1, 2, 3, 4, 5 carbon chain, the double bond between carbons 2 and 3 and a methyl group on carbon 2.
00:23
And we are reacting this with methanol and mercury acetate, followed by sodium borohydride.
00:48
So rhodium borohydride.
00:52
All right.
00:56
So to reason about this product, i think the best way we can do that is to just step through the mechanism.
01:02
So recall that we'll have mercury both being attacked by the double bond while the mercury attacks the carbon with the double bond.
01:22
This will give us the following.
01:30
Sort of cyclic.
01:37
All right.
01:38
One of these is going to take off.
01:44
This will be on one face of the molecule, by the way.
01:47
And then our alcohol will attack the more substituted carbon...