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In this particular video, we're going to discuss the question.
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Predict the product of the subunification of methyl oleate with sodium hydroxide.
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So here we will subpoenification reaction, a reaction which is used to produce soap in the presence of sodium hydroxide, potassium hydroxide.
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So here the main product formed is soap, the formation of soap by the process of sponification reaction.
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So here we have reactants are methyl, methyl, oleate, plus sodium hydroxide.
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So reactant may be fed are oil and with sodium hydroxide and formed soap and glycerol.
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So here formula of methyl oil is carbon 19 hydrogen 36 and oxygen 2 plus n -a -o -h and this will produce soap so plus glycerol and here the structure of open structure of methyl oleate is we'll draw the open structure and this is oxygen methyl group and carbonal group and this is carbon carbon carbon double bonded with oxygen atom and number of one two three four five six seven eight eight nine here double bond and hydrogen atom and nine ten eleven twelve thirteen fourteen fifteen sixteen and sixteen and here seventeen seventeen and seventeen and here seventeen and this is structure of here we have number of carbon atoms are one and two three four five six seven eight nine ten eleven twelve thirteen fourteen fifteen sixteen sixteen seventeen eighteen nineteen number of carbon atom nineteen and number of hydrogen thirty six and oxygen atoms two one two and one double bound here and this is called methyl oleate so this react with sodium hydroxide and the product formed here is the product formed here is here this will sodium and hydroxide well here any or h this will sodium this side will here we will write this will here from this side this will break this is break here and this is i'm sorry here this is break from here n -a -o -h n -a -o -h this break from this side and and here we will show the product and this will attach with this and this will separate from the n -a -o hydrogen will separate from here and here we will draw the structure product we can say soap this will formed here we will draw here form here one two three four five six seven eight nine and double wound hydrogen ten eleven twelve thirteen fourteen fifteen sixteen sixteen seventeen eighteen eighteen and nineteen here carbonyl group and this will attach with n a or n a negative charge, positive charge.
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And this is plus ch3.
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We have ch3.
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Oh, h.
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This will separate out from here...