00:02
Given regression summary table as the t test statistic value is calculated for regression coefficients as bi divided by standard error of bi.
00:20
Here first for a is b1 equal to 3 .52 and standard error of b1 .5.
00:35
Thus t value is 2 .52 divided by 0 .45, which is equal to 7 .82.
00:49
Thus t test statistic value for b1 is 7 .82.
00:55
For weight variable, standard error value is 0 .96 and t value is 0 .96 and t value is minus 6 .73.
01:10
Now we have to find the coefficient of variable that is b1 equal to 3 test statistic into standard error of b2 so minus 6 .73 into 0 .96 equal to minus 6 .46 thus coefficient of weight is minus 6 .46.
01:46
For heart rate variable, coefficient value b3 equal to minus 5 .45 and t test statistic value is minus 3 .45.
01:59
Now we have to find standard error of b3 which is minus 5 .45 divided by minus 3 .5 .5.
02:08
Which is 1 .58.
02:11
The standard error for coefficient of outright is 1 .58.
02:20
Now we have to find residual standard error which is root over rss divided by n minus 2, where rss is regression sum of squares which is given as from an nova table, the regression sum of space is 435 .62.
02:45
So 435 .62 divided by here n is total decrease of freedom is given as 28, that is n minus 1 equal to 28, such that n equal to 28 plus 1 equal to 29.
03:03
So residual sum of space s equal to 4 .017...