Question 1: Prove that $S_n$ is true for all natural number $n$ $2^3 + 4^3 + 6^3 + \dots + (2n)^3 = 2n^2(n+1)^2$
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When n=1, the equation becomes 2*1^2 + 1 = 2*1*1 + 1 = 2+1 = 3. So, the base case holds true. Show more…
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