Prob 1: The density of conduction electrons in a semiconductor sample is \(10^{23} \frac{\text{conduction electrons}}{m^3} \). A voltage is applied to the semiconductor such that the conduction electrons have an average drift velocity of \(-2a\frac{m}{s}\). What is the current density? The charge on an electron is -1.6x10$^{-19}$ C.
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- Electron density (\( n \)) = \( 10^{23} \, \text{m}^{-3} \) - Charge of an electron (\( e \)) = \(-1.6 \times 10^{-19} \, \text{C} \) - Drift velocity (\( v_d \)) = \(-2a \, \text{m/s} \) Show more…
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