Show that frac{P(H|E)}{P(G|E)} = frac{P(H) cdot P(E|H)}{P(G) cdot P(E|G)}
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Step 1
First, we know that the conditional probability of an event A given an event B is defined as: $P(A \mid B) = \frac{P(A \cap B)}{P(B)}$ Now, let's apply this definition to the given expression: $\frac{P(H \mid E)}{P(G \mid E)} = \frac{\frac{P(H \cap Show more…
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