00:01
Hello in this question we are given the arrangement is something like this there is a vertical road a b ac let me draw it this is some ac this is a b this is a b and this is c b this is a this is a and this is c this is b okay here at b it is a roller at a it is a hinge okay and a force of 40 kiloiter is acting on over here this is the given situation and dimensions are 1 .5 meter and 2 meter and 2 .0 meter okay we need to calculate stress in all the members okay so for that matter first of all we will calculate the forces in all the members and then we will divide them with the area to get the required stresses so here it would be vb here it would be va and here it would be h at a.
01:12
Okay, so when we will do summation of horizontal forces, what do we get? 7, sorry, 40 minus h .a must be equal to 0.
01:26
This is what we get from sigma, a horizontal, that must be equal to 0.
01:33
So from here we get h .a value is 40.
01:37
Let me write it.
01:39
Sorry, for the interruption.
01:55
So h .a is sorry, there is.
01:59
There was some problem with the pc.
02:03
So h is coming out to be 40 kiloton.
02:09
Now similarly, when we do summation of moment about a, what do we get? 40 into 1 .5, that is clockwise movement minus vb into 2, that is anti -cloquoise moment.
02:27
That must sums out to be 0.
02:28
Okay, so from here we get our value of vb would be 30 kilo nettle.
02:40
So the situation is something like this.
02:46
Forty is acting over here, 40 is acting over here, 30 is acting over here and 30 is acting over here.
02:55
So when we balance forces at a, the forces are downright it is 30, horizontal it is 40, and this force is force in member, a, b.
03:13
Similarly, this is force in member ac.
03:18
So from here when we balance forces in horizontal and vertical directions respectively, we get f .a .b is 40 kilonetan and fac is 30 kilo -neutral...