Question

Problem 1. Air enters a compressor with a pressure of 120 kPa and a temperature of 310K. The mass flow rate of the air is 2.5 kg/s. Heat transfer from the compressor to the surroundings is 23 kJ per kg of air. The air exits the compressor at a pressure of 800 kPa and a temperature of 544K. Neglect kinetic and potential energy effects. Determine the power required (in kW) to run this compressor. Assume ideal gas behavior, with constant specific heats as given below. For air, use R = 0.2870 kJ/kg-K, $C_p$ = 1.006 kJ/kg.K, $C_v$ = 0.718 kJ/kg.K

          Problem 1. Air enters a compressor with a pressure of
120 kPa and a temperature of 310K. The mass flow rate
of the air is 2.5 kg/s. Heat transfer from the compressor
to the surroundings is 23 kJ per kg of air. The air exits
the compressor at a pressure of 800 kPa and a
temperature of 544K. Neglect kinetic and potential
energy effects. Determine the power required (in kW)
to run this compressor.
Assume ideal gas behavior, with constant specific heats
as given below.
For air, use R = 0.2870 kJ/kg-K,
$C_p$ = 1.006 kJ/kg.K,
$C_v$ = 0.718 kJ/kg.K

Show more…

Problem 1. Air enters a compressor with a pressure of
120 kPa and a temperature of 310K. The mass flow rate
of the air is 2.5 kg/s. Heat transfer from the compressor
to the surroundings is 23 kJ per kg of air. The air exits
the compressor at a pressure of 800 kPa and a
temperature of 544K. Neglect kinetic and potential
energy effects. Determine the power required (in kW)
to run this compressor.
Assume ideal gas behavior, with constant specific heats
as given below.
For air, use R = 0.2870 kJ/kg-K,
Cp = 1.006 kJ/kg.K,
Cv = 0.718 kJ/kg.K

Added by Soledad G.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Kritika Mishra

Step 1

The change in enthalpy can be calculated using the equation: ΔH = Cp * ΔT where ΔH is the change in enthalpy, Cp is the specific heat at constant pressure, and ΔT is the change in temperature. ΔT = T_out - T_in = 544 K - 310 K = 234 K ΔH = 1.006 kJ/kgK * 234 K = Show more…

Show all steps

lock

Thanks for your feedback!

Problem 1. Air enters a compressor with a pressure of 120 kPa and a temperature of 310 K. The mass flow rate of the air is 2.5 kg/s. Heat transfer from the compressor to the surroundings is 23 kJ per kg of air. The air exits the compressor at a pressure of 800 kPa and a temperature of 544 K. Neglect kinetic and potential energy effects. Determine the power required (in kW) to run this compressor. Assume ideal gas behavior, with constant specific heats as given below. 23 kJ/kg P = 800 kPa, T = 544 K AIR m = 2.5 kg/s W_in P = 120 kPa, T = 310 K For air, use R = 0.2870 kJ/kgK. Cp = 1.006 kJ/kgK, Cv = 0.718 kJ/kgK

Play audio

Feedback

Powered by NumerAI

Kritika Mishra and 85 other subject Physics 101 Mechanics educators are ready to help you.

Ask a new question

Labs

Want to see this concept in action?

NEW

Explore this concept interactively to see how it behaves as you change inputs.

View Labs

Key Concepts

Recommended Videos

Recommended Textbooks

Ace is your personal tutor. It breaks down any question with clear steps so you can learn.

Start Using Ace

Continue solving this problem

Create a free account to:

View full step-by-step solution
Ask follow-up questions with Ace AI
Save progress and study later