Problem 1
Determine the principal stresses and maximum shear stress acting at point B which is located just on the web, below the horizontal segment on the cross section. Show the results (principal stresses) on a properly oriented element located at this point.
$$I = \frac{1}{12}(15)(130)^3 + \frac{1}{12}(150)(12)^3 = 276780 \text{ mm}^4$$
$$A = [(15)(130) + (150)(12)] = 2112 \text{ mm}^2$$
$$M_{AB} = 0 + \uparrow = -6(\frac{3}{5})(800) - 6(\frac{4}{5})(300) - M_{AB} \rightarrow M_{AB} = 4320 \text{ kN}$$
800 mm
300 mm
150 mm
12 mm
130 mm
15 mm
6 kN