00:02
In this problem, we need to find the angular velocity of the gymnast when she swings around the bar to an angle of 135 degrees.
00:12
Okay, so i have here a sketch of the problem.
00:15
So the gymnast coming from position 1 drops from a height h and her hands strike the bar.
00:23
So that's position 2 and 3.
00:25
And she swings on it until she reaches position 4.
00:29
So the sketch includes the dimensions, the given value, so h is 0 .5 meter.
00:37
The mass moment of inertia i is also given 7 .5 kilogram meter squared.
00:44
And then the distance from the center of the girls, the gymnasts center of mass is 0 .75 meter.
00:53
And then the angle here is 135 degrees.
00:59
Okay, so i'm going to apply the work energy theorem for position 1 and 2, considering position 1 and 2.
01:10
So let's write first the equations okay.
01:14
1 plus gravitational potential energy 1 plus elastic potential energy 1 plus work non -conservative equals kinetic energy 2 plus gravitational potential energy 2, plus gravitational potential energy 2, plus elastic potential energy 2.
01:32
Actually, most of this will be cancelled.
01:35
So we have no zero kinetic energy 1.
01:38
Then we have no elastic.
01:40
We have no work non -conservative.
01:43
Now, for position 2, we don't have the gravitational potential energy because, as you can see in the figure, our reference line is the broken lines, the red broken lines...