Problem 1: The rigid beam BC shown in Figure is supported by rods (1) and (2) that have cross-sectional areas of 100 mm² and 2300 mm², respectively. For a uniformly distributed load of w = 40 kN/m, determine the normal stress in each rod. Assume L = 3 m and a =1.5 m. Answer: $sigma_{AB}$ = 150 MPa, $sigma_{BC}$ = 19.56 MPa Problem 2: For the connection shown, determine the average shear stress produced in the 1/2- in. diameter bolts if the applied load is P = 1,200 lb. Answer: $ au_{bolt}$ = 1.53 ksi Problem 3: The beam shown is supported by a pin at C and by a short link AB. If w = 20 kN/m, determine the average shear stress in the pins at A and C and average normal stress in short link AB. Each pin has a diameter of 25 mm and short link AB has a diameter of 30 mm. Assume L = 2.0 m and $ heta$=30°. Answer: Pin A (single shear) $ au_A$ = 81.5 MPa, $sigma_{AB}$ = 56.5 MPa, Pin C (double shear) $ au_C$ = 40.75 MPa
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- Total resultant W = w · a = 40 kN/m · 1.5 m = 60 kN, located at a/2 = 0.75 m from the left end. - Take moments about left support: R_right · L = W · 0.75 ⇒ R_right = (60 kN · 0.75 m) / 3.0 m = 15 kN. - R_left = W − R_right = 60 − 15 = 45 kN. Show more…
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