00:01
Hello everyone according to the question the solution as follows first let us see the question here okay so here is the question like this i'm making a rough diagram here check it here they're placing the charge a that is qa one corner q b second corner qc third corner qd the fourth corner and center at i'll consider it is o they're placing q now remember they have given the values also here so let us write the value of the charges saying that given i'll mention that diagram i just modified and they're written like this qb equals to qc is equals to qd is equal to 3 .1 nanoculum and and they're saying q, which is placed at center, that is minus 0 .2 nanoculum.
01:14
Okay? and they're asking here question, the electric field at qa.
01:22
What will be the electric field at the position a by charge b, c, d and q? for that, what we can do, see, suppose if i consider diagonals, we have to find, and side of the square also has given.
01:40
So side of the square he is telling, i'll convert directly to the meter.
01:44
I'm writing 0 .06 meter.
01:47
All the side is going to become 0 .06 meter.
01:53
Okay, so diagonals we have to find.
01:57
Okay.
01:58
First, see that electric field from b, from b at a, i can say this is e b.
02:08
Then electric field from c at a, i can say this is going to become ec.
02:17
Then from d, it is going to become ed.
02:21
But ed is making some angle so that we have to resolve along x and y axis.
02:25
So that will see later.
02:27
And from center charge, electric field is producing that is negative charge.
02:33
So therefore, we can consider backward direction.
02:37
This electric field from eq okay so these all four charges are giving our electric field at a that we can find one by one now so see here first we can find the diagonal of square so that we can use the pythagoras theorem and we can say that here see a d or we can say b c both diagonal either ad or bc anything you can call so that i'm going to get under the root of side square into sides plus side square so that is 0 .06 square plus 0 .06 square so this we are getting the answer around 0 .0072 this is under the root then after the route we are getting like 0 .08 48 meter what is this either ad or bc you can say bc or ad that is the distance or diagonal and half of that suppose if you want at center distance like a o we can say that that also let us find a .o b b o c o or d o half of that half of that we can say point zero four two four meter okay so this distance we're getting point zero four two four half distance here again point zero four two four four one second here point zero four two four one second here point zero four two similar way here also point zero four two four fine anyway all the side we can mention that after this we'll go to now electric field one by one check it we can say initially electric field electric field at a or qa whatever we can say electric field at a by q a by q a b okay from the charge q b at a electric field we can say that e b is equal to i'll mention e b is equal to here i will mention minus of k k means that is we know electric field formula k directly i will mention here 9 into 10 to the power of 9 value so see that 9 into 10 to the per of 9 into charge of qb.
05:58
Qb charges 3 .1 into 10 to the part of minus 9 divided by 0 .06 is the distance square that.
06:10
Okay, you'll get here minus meaning is see here.
06:15
Suppose if we consider like this is x axis one second here.
06:22
This will be i'll take x axis.
06:25
This will be y -axis okay whichever electric field is coming this direction that is plus if it is going opposite minus if it is coming up it is plus if it coming down minus so therefore now eb you can check it eb is going backward so therefore i'll take it is minus fine so similar way i'm going to apply for all the things see how to check it here the answer is going to become for e b we are getting minus 7 ,750 newton per column this is electric field at a by q b similar way we can find electric field electric field at a by qc charge c that you can check, we can say here ec is equal to.
07:31
Anyway, it is going along the direction.
07:33
I'll keep it as plus...