Question

Problem 11.13 8 of 14 Review | Constants Part A A 1.65 kg mass stretches a vertical spring 0.285 m. If the spring is stretched an additional 0.130 m and released, how long does it take to reach the (new) equilibrium position again? t = Value Units Submit Request Answer

Name: problem 1113 8 of 14 review constants part a a 165 kg mass stretches a vertical spring 0285 m if the spring is stretched an additional 0130 m and released how long does it take to reach the 98457
Uploaded: 2022-03-15T10:16:09-08:00
Duration: 2 min 18 s
Channel: Prabhu Ramji
Description: problem 1113 8 of 14 review constants part a a 165 kg mass stretches a vertical spring 0285 m if the spring is stretched an additional 0130 m and released how long does it take to reach the 98457

          Problem 11.13
8 of 14
Review | Constants
Part A
A 1.65 kg mass stretches a vertical spring 0.285 m.
If the spring is stretched an additional 0.130 m and released, how long does it take to reach the (new) equilibrium position again?
t = Value Units
Submit
Request Answer

problem 1113 8 of 14 review constants part a a 165 kg mass stretches a vertical spring 0285 m if the spring is stretched an additional 0130 m and released how long does it take to reach the 98457

Added by Elisa B.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Prabhu Ramji

03/15/2022

Step 1

When a mass is hung from a vertical spring, at equilibrium, the gravitational force equals the spring force. Given: Mass m = 1.65 kg Stretch x = 0.285 m Acceleration due to gravity g = 9.8 m/s^2 The force due to gravity is $F_g = mg$. The force due to the spring Show more…

Show all steps

Thanks for your feedback!

Problem 11.13 8 of 14 Review | Constants Part A A 1.65 kg mass stretches a vertical spring 0.285 m. If the spring is stretched an additional 0.130 m and released, how long does it take to reach the (new) equilibrium position again? t = Value Units Submit Request Answer