Problem 13 of 15 Move the point on the graph to determine the rate at time 1.21 seconds. [Reactant] (M) (0,4) -rate = 5.32 time (s) Answer:
Added by Bailey C.
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21 s and read its concentration. From the graph that point is approximately (1.21 s, 3.36 M). Show more…
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Time and concentration data were collected for the reaction A → products t (s) | [A] (M) 0 | 0.52 20 | 0.43 40 | 0.34857 60 | 0.28538 80 | 0.23365 100 | 0.19130 The blue curve is the plot of the data. The straight orange line is tangent to the blue curve at t = 40 s. Approximate the instantaneous rate of this reaction at time t = 40 s. instantaneous rate: [ ] M/s
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Time and concentration data were collected for the reaction A → products | t (s) | [A] (M) | |---|---| | 0 | 0.52 | | 20 | 0.43 | | 40 | 0.35 | | 60 | 0.29 | | 80 | 0.23 | | 100 | 0.19 | The blue curve is the plot of the data. The straight orange line is tangent to the blue curve at t = 40 s. Approximate the instantaneous rate of this reaction at time t = 40 s. instantaneous rate: [ ] M/s
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Time and concentration data were collected for the reaction A ⟶ products | t (s) | [A] (M) | |---|---| | 0 | 0.52 | | 20 | 0.43 | | 40 | 0.35 | | 60 | 0.29 | | 80 | 0.23 | | 100 | 0.19 | The blue curve is the plot of the data. The straight orange line is tangent to the blue curve at t = 40 s. Approximate the instantaneous rate of this reaction at time t = 40 s. instantaneous rate: [ ] M/s
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