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Problem 14.11: A proton was accelerated to a speed of v = 0.9c. Its rest mass is mp = 0.9383 GeV/c² (Giga-electron-volt-kilogram per Joule). What is the magnitude of each type of relativistic dynamic concept for this proton such as: a) Rest Energy b) Relativistic Momentum c) Relativistic Kinetic Energy d) Total Relativistic Energy Given values: • v = 0.9c • mp = 0.9383GeV/c² Solution 14.11: Preliminary Solutions: v/c = 0.9 v²/c² = 0.81 1-(v²/c²) = 0.19 ?[1-(v²/c²)] = 0.436 1/?[1-(v²/c²)] = ? = 2.294 a) EP = mp c² = (0.9383 GeV/c²)c² = 0.9383 GeV b) p = ?mpv = (2.294)(0.9383 GeV/c²)(0.9c) = 1.94 GeV/c c) Ek = mpc²(? - 1) = (0.9383 GeV/c²)c²(2.294-1) = 1.214 GeV d) The equation ? reduces to equation ? since the "pc" part is zero (0). Answer is also the

          Problem 14.11:
A proton was accelerated to a speed of v = 0.9c. Its rest mass is mp = 0.9383 GeV/c² (Giga-electron-volt-kilogram per Joule). What is the magnitude of each type of relativistic dynamic concept for this proton such as:
a) Rest Energy
b) Relativistic Momentum
c) Relativistic Kinetic Energy
d) Total Relativistic Energy
Given values:
• v = 0.9c
• mp = 0.9383GeV/c²

Solution 14.11:
Preliminary Solutions:
v/c = 0.9 v²/c² = 0.81 1-(v²/c²) = 0.19
?[1-(v²/c²)] = 0.436
1/?[1-(v²/c²)] = ? = 2.294
a) EP = mp c²
= (0.9383 GeV/c²)c²
= 0.9383 GeV
b) p = ?mpv
= (2.294)(0.9383 GeV/c²)(0.9c)
= 1.94 GeV/c
c) Ek = mpc²(? - 1)
= (0.9383 GeV/c²)c²(2.294-1)
= 1.214 GeV
d) The equation ? reduces to equation ? since the "pc" part is zero (0). Answer is also the

Problem 14.11:
A proton was accelerated to a speed of v = 0.9c. Its rest mass is mp = 0.9383 GeV/c² (Giga-electron-volt-kilogram per Joule). What is the magnitude of each type of relativistic dynamic concept for this proton such as:
a) Rest Energy
b) Relativistic Momentum
c) Relativistic Kinetic Energy
d) Total Relativistic Energy
Given values:
• v = 0.9c
• mp = 0.9383GeV/c²

Solution 14.11:
Preliminary Solutions:
v/c = 0.9 v²/c² = 0.81 1-(v²/c²) = 0.19
?[1-(v²/c²)] = 0.436
1/?[1-(v²/c²)] = ? = 2.294
a) EP = mp c²
= (0.9383 GeV/c²)c²
= 0.9383 GeV
b) p = ?mpv
= (2.294)(0.9383 GeV/c²)(0.9c)
= 1.94 GeV/c
c) Ek = mpc²(? - 1)
= (0.9383 GeV/c²)c²(2.294-1)
= 1.214 GeV
d) The equation ? reduces to equation ? since the "pc" part is zero (0). Answer is also the

Added by Cory M.

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