Question

Problem #1: Energy Storage A robot battery is rated at 90 A-h, meaning that under certain test conditions it can output 2A at 6V for 45 hours. a) How much energy is stored in the battery (in Joules)? P = VI P = 12 P = 194,40000 b) Suppose the battery is used to power a motor that consumes 36W. How long can the motor run before half of the energy in the battery is used? 36W 7.5 h \frac{1944000}{2} \frac{97200}{36} = 2700

          Problem #1: Energy Storage
A robot battery is rated at 90 A-h, meaning that under certain test conditions it can output
2A at 6V for 45 hours.
a) How much energy is stored in the battery (in Joules)?
P = VI
P = 12
P = 194,40000
b) Suppose the battery is used to power a motor that consumes 36W. How long can
the motor run before half of the energy in the battery is used?
36W
7.5 h
\frac{1944000}{2}
\frac{97200}{36} = 2700

Problem #1: Energy Storage
A robot battery is rated at 90 A-h, meaning that under certain test conditions it can output
2A at 6V for 45 hours.
a) How much energy is stored in the battery (in Joules)?
P = VI
P = 12
P = 194,40000
b) Suppose the battery is used to power a motor that consumes 36W. How long can
the motor run before half of the energy in the battery is used?
36W
7.5 h
(1944000)/(2)
(97200)/(36) = 2700

Added by Oscar W.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Lazar Cvijovic

09/16/2019

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Problem #1:Energy Storage A robot battery is rated at 90 A-h, meaning that under certain test conditions it can output 2A at 6V for 45 hours. Show more…

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Problem #1: Energy Storage A robot battery is rated at 90 A-h, meaning that under certain test conditions it can output 2A at 6V for 45 hours. a) How much energy is stored in the battery (in Joules)? P = VI P = 12,000 J b) Suppose the battery is used to power a motor that consumes 36W. How long can the motor run before half of the energy in the battery is used? 36W = 2.4 x 10^4 J 36/97200 = 0.00037037 hours 72.1 hours