Problem 2 15 pts) Let the expected value of wind speed at 10 meters height be:
$$\mathcal{E}(V_{10}) = \int_{-\infty}^{\infty} v_{10}f_{V_{10}}(v_{10}) dv_{10}$$
where $f_{V_{10}}$ is the probability density function of wind speed observed at 10 meters heigth.
If the wind speed at height $h$ is $v_h = v_{10} (\frac{h}{10})^a$, what is the expected value of $v_h$ or simply $\mathcal{E}(V_h)$ in terms of $\mathcal{E}(V_{10})$?
Hint: Let $X$ a random variable with probability density function $f_X$. Also, let $q: \mathbb{R} \mapsto \mathbb{R}$ a real-value function. The expectation $\mathcal{E}$ of $q(X)$ is:
$$\mathcal{E}(q(X)) = \int_{-\infty}^{\infty} q(x) f_X(x) dx$$