Problem 2 A delta connected resistive load is connected across a balanced three phase supply of 400 V as shown in the figure where $V_{AB} = 400\angle0$, $V_{BC} = 400\angle-120$ and $V_{CA} = 400\angle-240$. Find first the currents $I_{ab}$, $I_{bc}$ and $I_{ca}$ flowing in the resistors and then find the symmetrical components of the delta currents $I_{ab1}$, $I_{ab2}$ and $I_{ab0}$

          Problem 2
A delta connected resistive load is connected across a balanced three phase supply of 400 V as
shown in the figure where $V_{AB} = 400\angle0$, $V_{BC} = 400\angle-120$ and $V_{CA} = 400\angle-240$. Find first the
currents $I_{ab}$, $I_{bc}$ and $I_{ca}$ flowing in the resistors and then find the symmetrical components of the
delta currents $I_{ab1}$, $I_{ab2}$ and $I_{ab0}$

Problem 2
A delta connected resistive load is connected across a balanced three phase supply of 400 V as
shown in the figure where VAB = 400∠0, VBC = 400∠-120 and VCA = 400∠-240. Find first the
currents Iab, Ibc and Ica flowing in the resistors and then find the symmetrical components of the
delta currents Iab1, Iab2 and Iab0

Added by Victoria B.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Abdul Khalad

Step 1

The line voltage Vab is given by Vab = Vca - Vbc. Vab = 400<-240 - 400<-120 = 400<(-240-(-120)) = 400<-120 The line current Iah can be found using Ohm's Law: Iah = Vab / 15 Ω. Iah = 400<-120 / 15 Ω = (400/15)<-120 = 26.67<-120 A Show more…

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A delta-connected resistive load is connected across a balanced three-phase supply of 400 V, as shown in the figure. The variables VAR, VBc, and Vca are given as VAR = 400<0, VBc = 400<-120, and Vca = 400<-240. First, find the currents Iah, Ite, and Ia flowing in the resistors. Then, find the symmetrical components of the delta currents Iah!, Ishz, and Iamu. 15 Î© 20 Î© 250 Î©