00:01
Here in this question we have to find out the values of current and potential difference value in the circuit given in the question.
00:09
Right, so let's go ahead.
00:11
But we will apply kcl at b.
00:20
So after applying this, we will get the equation which is i4 minus of i3 plus i5 that's equal to 0.
00:28
So from here this i4 minus of 10 plus vb divided by 5 that's equal to 0.
00:37
So from here this i4 is equal to 10 minus of vb divided by 5 and from here the i4 we will get that's equal to 10 minus of okay 5 upon 3 divided by 5 that means we can say that this is what the thing like vb value is there that is 5 divided by 3.
00:58
So from here we will get the i4 value as equal to 9 .666 ampere.
01:05
So we got the first one value that is i4.
01:07
Let's go ahead that is we know that v5 is equal to v4 from the circuit only.
01:15
This is equal to 5 of i2.
01:18
So this is 5 of i2.
01:21
So this is 5 multiplied by 1 upon 3.
01:23
So this is equal to 5 divided by 3 volts.
01:27
So here v4 is equal to v5 which is equal to 5 upon 3 volts we got over here.
01:34
After that we will go that is v1 is equal to 2 volt which is there in the question but i1 is equal to that's equal to 10 .334 ampere.
01:47
Okay we got the another value also.
01:50
After that v1 is equal to v2...