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Cell Voltage / V 12- Charge Discharge 1.0- 0.82 V 0.95 V 1.56 Ah 0.8 0.74 V 0.59 V 06- 1.37 Ah 0.0 0.5 1.0 1.5 Capacity/Ah 

          Cell Voltage / V
12-
Charge
Discharge
1.0-
0.82 V
0.95 V
1.56 Ah
0.8
0.74 V
0.59 V
06-
1.37 Ah
0.0
0.5
1.0
1.5
Capacity/Ah
Cell Voltage / V 12- Charge Discharge 1.0- 0.82 V 0.95 V 1.56 Ah 0.8 0.74 V 0.59 V 06- 1.37 Ah 0.0 0.5 1.0 1.5 Capacity/Ah

Added by Cynthia B.

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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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Problem 2. A hypothetical flow battery demonstrates the following charge-discharge profiles. Calculate coulombic efficiency and energy efficiency for this cycle. GIVE PROPER ASSUMPTIONS Cell Voltage/V 0.0 06 0.8 1.0 12 0.74V 0.82 V 1 Discharge -Charge 0.5 Capacity IAh 1.0 1.37 Ah A6S0 1.56 Ah 0.95
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00:01 High in the quotient it is given that we have z1 is equal to 0 .99 we have z2 is equal to 0 .97 we have q1 is equal to 31 ampere hour and we have q2 is equal to 32 ampere hour we have z minimum is equal to 0 .1 and we have ocv is equal to 3 .3 now present change capacity in battery will be q1 bar will be equal to 31 multiplied by 0 .99 ampere hour so this will be equal to 30 .69 ampere hour and we have q2 bar is equal to 32 multiplied by 0 .97 ampere hour so this will be equal to 31 .04 ampere hour now when two batteries having different charge capacity connect it connect it will cause damage to each other so for calculation we will take average of capacity so will be equal to 30 .69 plus 31 .04 upon 2 so this will be equal to 30 .865 ampere hour so when two batteries connect in series then total ocv will be equal to 2 multiplied by ocv which will be equal to 2 multiplied by 3 .3 which is equal to 6 .6 volt now…
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